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OpenStudy (deathslasher99):
Simplify and write answer in standard form:
(7f)(pv + 17f)
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OpenStudy (deathslasher99):
Would the answer be 119?
OpenStudy (deathslasher99):
Please let me know when you can if i am correct or incorrect
OpenStudy (deathslasher99):
Thanks.
OpenStudy (lord_box):
You need to distribute (7f) to the (pv + 17f)
OpenStudy (deathslasher99):
ok
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OpenStudy (deathslasher99):
So how would you write the answer?
OpenStudy (lord_box):
Mind showing me what you have so far?
OpenStudy (deathslasher99):
k
OpenStudy (deathslasher99):
Give me a sec
OpenStudy (deathslasher99):
7f(pv+17f)
=(7f)(pv+17f)
=(7f)(pv)+(7f)(17f)
=7fpv+119f2
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OpenStudy (sainath):
deathslasher can u help me on mine?? It's really important
OpenStudy (lord_box):
That's right, and in standard form, what order of exponents do we list terms in?
OpenStudy (deathslasher99):
And by the way just hope you know that i just want to know how to write the answer down.
OpenStudy (deathslasher99):
Because it is trough an online process and i dont know how i ma supposed to write it down
OpenStudy (lord_box):
Recall the standard form for a quadratic equation, ax^2 + bx + c, the highest power of x is at the beginning.
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