Write the sum using summation notation, assuming the suggested pattern continues. -9 - 3 + 3 + 9 + ... + 81
What does it look like is happening to each term?
they are adding 6
Alright, and it starts from -9, how would you represent that using summation notation?
im not sure
\[\sum_{n=0}^{?} -9 + ?\] This is what you know so far. What could you add to the -9 to show that you're adding 6 , then 12, then 18, etc every time?
6n
That's right. Now how many times would you have to add 6n to get to 81?
15
Alright, \[\sum_{n=0}^{15} -9 + 6n\] This is how you build it in summation notation, or alternatively, \[\sum_{n=11}^{16} -9 + 6(n-1)\], same thing
The second one should read n=1, sorry
thank you so much for the help
You're welcome
write it like \[\sum_{n=1}^{16}\left\{ -9+\left( n-1 \right)6 \right\}\] \[=\sum_{n=1}^{16}\left( 6n-15 \right)\]
-9 - 3 + 3 + 9 + ... + 81 Write it following the order of PEMDAS.
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