Given s=t^2-5t+6
calculate the distance travelled,in m,in the fifth second. @jim_thompson5910

Question

Given s=t^2-5t+6
calculate the distance travelled,in m,in the fifth second. @jim_thompson5910

jim_thompson5910 · Answer

What are the roots (x intercepts) of y = x^2 - 5x + 6 ?

marc_d · Answer

x=3 and x=2

jim_thompson5910 · Answer

actually, s is often a position function. Is that what your book is saying?

marc_d · Answer

yess ^

marc_d · Answer

so,what should we do next?

jim_thompson5910 · Answer

one moment

sshayer · Answer

calculate s5-s4
i.e.,t=5 and t=4

marc_d · Answer

okay,i think i got it.. ^
Thank you @jim_thompson5910  @sshayer  :)

jim_thompson5910 · Answer

if you graphed y = x^2-5x+6, you'll find that the min is (2.5, -0.25)

the largest y gets on the interval [0,5] is y = 6
the smallest y gets is y = -0.25

the distance between those two y values is what?

marc_d · Answer

is it 6.25?

jim_thompson5910 · Answer

yes so on the first half of the parabola, you go 6.25 and the same for the second half

2*6.25 = 12.5 is the total distance traveled

marc_d · Answer

okay..