Question

Solution for sin2x(1+y²)+sin²x y'=0

Answer 1

separation of variables didn't work?

Answer 2

- sin2x/sin^2 x dx = dy/(1+y^2)

simplify left side more.
then integrate

Answer 3

-2tanx dx =dy/(1+y²)
What now?

Answer 4

If we follow your method we have to ∫(1/1+y²). How should I do that?

Answer 5

I think i get it

Answer 6

Thank you for help

Answer 7

cool :)
integral 1/1+y^2 dy is pretty standard.
and welcome ^_^

Answer 8

Thank you for help