Question

Equation 1) p = kl^(1/2)
Equation 2) T = 2π√L/g
In equation 1, p = period and l = length.
In equation 2, T = pendulum period, L = pendulum length, and g = gravity. This is the equation for the period of a pendulum.
How does equation 1 relate to equation 2?

Answer 1

square both sides of both equations, you have
\(p^2 = kl\\T^2 = 2\pi l/g\)
if you solve for l from the first one and then replace to l on the second one, you have the relationship between p and T

Answer 2

So l = p^2 / k

Answer 3

yup

Answer 4

Thank you.

Answer 5

np