Question

solve for x

Answer 1

\[\sqrt{x^2-9}=x-1\]

Answer 2

square both sides

Answer 3

x^2-9=x^2+10

Answer 4

but how do i get it so the two x^2 don't cancel out?

Answer 5

No?
\[\sqrt{x^2-9}=x-1 \\ \\ x^2-9= (x-1)^2 \\ \\ x^2-9= (x-1)(x-1) \\ \\ x^2-9= x^2-2x+1 \\ \\ -9= -2x+1 \\ \\ ?\]

Answer 6

since i'm solving for x

Answer 7

ohhhhh

Answer 8

Good work Sam :)