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OpenStudy (jtug6):
multiply the 2 inside the the parenthesis first. 2*x and 2*(-5). And then add those. What do you get?
OpenStudy (shealyn):
2x+-10??????????/
OpenStudy (jtug6):
Yes! When you add a negative, you can just say the same thing as subtracting. So, 2x-10! Awesome. So, we still have that +4 though so we tag it on too. 2x-10+4. What's -10+4?
OpenStudy (shealyn):
-6
OpenStudy (jtug6):
yup! so now it's just, 2x-6 = 30. So we need to solve for x. What do you think we should do to both sides first?
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OpenStudy (shealyn):
add 6
OpenStudy (jtug6):
Yes! Great. So, 2x-6+6 = 30 + 6, right? so, 2x = 36. Now what? ^^
OpenStudy (shealyn):
divide 2 on both sides
OpenStudy (jtug6):
yes! . x = 36/2 = ?
OpenStudy (shealyn):
x=6
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OpenStudy (jtug6):
mmm, that'd be if it was 36/6, but it's 36/2 actually :P
OpenStudy (shealyn):
WAIT DUH ITS 18
OpenStudy (jtug6):
mhm! x = 18 :D
OpenStudy (shealyn):
Tysm lmao
OpenStudy (jtug6):
The great thing is, you can test it. Plug x = 18 back into the very first equation ;P
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