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Derivative question
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Find f'(a) \[f(x) = 3x^2 - 4x + 1\] We are supposed to use the derivative formula. So... 3(a+h)^2 - 4(a+h) + 1 all over h Right? Then I distributed, etc. and nothing seems to be canceling...
it would be f(a+h) - f(a) on the top
Your missing the -f(a) which does most of the cancelling.
Ohh I think I see what I did wrong.. hold on
The derivative is 3x + 3h - 4 right? Or should I plug in 0?
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well h is set to 0
you should get 6x-4 though
or rather 6a-4
I got 3a - 4 Where is the 6 coming from? D:
lets see if i expand i get 3a^2+6ah+3h^2-4a-4h+1-3a^2+4a-1 for the numerator.
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so 6ah+3h^2-4h after simplifying
for the numerator
Oh! :P Right. Thanks :)
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