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OpenStudy (prominer10000):
Last question! :)
Now this one really confuses me.
(12^-5)^2
-------- = 12
12^-4
Please help!
@TheSmartOne
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OpenStudy (prominer10000):
@TheSmartOne I see you're helping someone else, don't rush. Just come whenever you can, I can wait. I have all day today :)
OpenStudy (timamits):
please check the question once again.
OpenStudy (thewafflebro):
okay let me see what i can do here
OpenStudy (thewafflebro):
nvm the smart one got it :P
TheSmartOne (thesmartone):
Is the question supposed to be
\(\Large\frac{(12^{-5})^2}{12^{-4}} = 12^x\)
Is that all equal to 12^x?
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OpenStudy (prominer10000):
Yes, the X is the missing exponent.
TheSmartOne (thesmartone):
You need to use this property first:
\(\Large (a^b)^c = a^{bc}\)
and then you use this property
\(\Large \frac{x^y}{x^z} = x^{y-z}\)
OpenStudy (prominer10000):
Ok so, sorry. I'm really confused. So would I add the exponents together or no?
TheSmartOne (thesmartone):
no, you multiply the exponents in the numerator
OpenStudy (prominer10000):
So I do 12 x 5? Or do 12 x 12 x 12 x 12 x 12?
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TheSmartOne (thesmartone):
\(\Large (a^b)^c = a^{bc}\)
\(\Large (12^{-5})^2 = 12^{??}\)
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