Last question! :) Now this one really confuses me. (12^-5)^2 -------- = 12 12^-4 Please help! @TheSmartOne
@TheSmartOne I see you're helping someone else, don't rush. Just come whenever you can, I can wait. I have all day today :)
please check the question once again.
okay let me see what i can do here
nvm the smart one got it :P
Is the question supposed to be \(\Large\frac{(12^{-5})^2}{12^{-4}} = 12^x\) Is that all equal to 12^x?
Yes, the X is the missing exponent.
You need to use this property first: \(\Large (a^b)^c = a^{bc}\) and then you use this property \(\Large \frac{x^y}{x^z} = x^{y-z}\)
Ok so, sorry. I'm really confused. So would I add the exponents together or no?
no, you multiply the exponents in the numerator
So I do 12 x 5? Or do 12 x 12 x 12 x 12 x 12?
\(\Large (a^b)^c = a^{bc}\) \(\Large (12^{-5})^2 = 12^{??}\)
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