Draw 150° in standard position. Then find a if the point (a, 1) is on the terminal side of 150°.
Which quadrant would point (a,1) occupy? In that quadrant, which sign does the "adjacent side" have, positive or negative? Have you drawn a ray representing 150 degrees in std. position? Have you marked the point on your drawing?
Would the point be the vertex? I believe the quadrant would be the second one since it's over 90 degrees.
Yes, your ray would be correctly placed if drawn in Quadrant 2. What do you mean by "vertex" in this case? I'd say the ray has an arrow tip, and that the point (a,1) lies at that tip. Please draw this situation. Use the Draw utility, below. Now draw a horiz. line thru that point, and also draw a vert. line. What are the x-and y-coordinates of that point?
Your x-coordinate is the point a. What is the numerical value of a?
Would it be -1 in this case?
Since it's in quadrant 2 of the graph..
|dw:1471490316355:dw|
Hellllooo
|dw:1471493602175:dw| now let's extract our triangle |dw:1471493652464:dw| and we're solving for a
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