Points A(7, -5), B(-1, -2), and C(-4, 6) form triangle ABC on a coordinate plane. According to its sides, triangle ABC is a(n) ____________ triangle
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so what kind of triangle would it be?
AB=sqr root(73) BC=sqr roo1(73) so it is an isoceles triangle
because two sides are equal
u know the distance formula, right??
not really. is it A squared+B squared=C squared?
nooo this is only in right angle triangle where sum of square of two sides = square of third side (longest side) and this is called pythagoras theorem
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so like a hypotenuse?
yes c is hypotenuse
thanks! that helped alot :)
You can apply the pythagoras here too. Just draw a perpendicular from A on BC. Then you will have two right angled triangles.
Distance formula is \[\sqrt{(x1-x2)^{2}+(y1-y1)^{2}}\]
sorry it will be y2
really again thanks to both of you
ur wlcm:)
Nah don't thank me she's done the question all by herself. :)
:D
No seriously. I just put in the perpendicular without which too the question was done. :P
:) :)
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