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Algebra 19 Online
OpenStudy (danni_joanaveil2):

Points A(7, -5), B(-1, -2), and C(-4, 6) form triangle ABC on a coordinate plane. According to its sides, triangle ABC is a(n) ____________ triangle

OpenStudy (visarika23):

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OpenStudy (danni_joanaveil2):

so what kind of triangle would it be?

OpenStudy (visarika23):

AB=sqr root(73) BC=sqr roo1(73) so it is an isoceles triangle

OpenStudy (visarika23):

because two sides are equal

OpenStudy (visarika23):

u know the distance formula, right??

OpenStudy (danni_joanaveil2):

not really. is it A squared+B squared=C squared?

OpenStudy (visarika23):

nooo this is only in right angle triangle where sum of square of two sides = square of third side (longest side) and this is called pythagoras theorem

OpenStudy (visarika23):

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OpenStudy (danni_joanaveil2):

so like a hypotenuse?

OpenStudy (visarika23):

yes c is hypotenuse

OpenStudy (danni_joanaveil2):

thanks! that helped alot :)

OpenStudy (aakashtomar):

You can apply the pythagoras here too. Just draw a perpendicular from A on BC. Then you will have two right angled triangles.

OpenStudy (visarika23):

Distance formula is \[\sqrt{(x1-x2)^{2}+(y1-y1)^{2}}\]

OpenStudy (visarika23):

sorry it will be y2

OpenStudy (danni_joanaveil2):

really again thanks to both of you

OpenStudy (visarika23):

ur wlcm:)

OpenStudy (aakashtomar):

Nah don't thank me she's done the question all by herself. :)

OpenStudy (visarika23):

:D

OpenStudy (aakashtomar):

No seriously. I just put in the perpendicular without which too the question was done. :P

OpenStudy (visarika23):

:) :)

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