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http://prnt.sc/c9nl33 how to find fnet? specifically 36.5 and theta 66
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I think its the magnitude equation of the vector. Fnet = squrt(x^2+y^2) and tan(66)
the sum of the x-components of \( F_1, F_2, F_3\) is 28.3+0-43.3 = -15 and the sum of the y-components is 28.3+30-25= 33.3 so Fnet is the vector <-15, 33.3> |dw:1472047358615:dw|
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