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Mathematics 7 Online
OpenStudy (quickstudent):

Is this correct? polygon similarity

OpenStudy (quickstudent):

image attached. question: The figures below are similar; explain what you know about the sides. my answer: If the two polygons are similar, than all the sides are proportional. So, BD/HF = DN/FA = NI/AI = IL/IT = LB/TH

OpenStudy (quickstudent):

@welshfella

OpenStudy (quickstudent):

@JoannaBlackwelder

OpenStudy (quickstudent):

@Awolflover1

OpenStudy (quickstudent):

@welshfella

OpenStudy (loser66):

If you want to get a correct ratio, you need arrange the order of the vertexes on the same order. Like this:

OpenStudy (loser66):

|dw:1472057720669:dw|

OpenStudy (loser66):

For larger one, starts from B go along the side and get the starting point of longer side DN (compare to BL) So that, for smaller one, HT is larger than AF, so, starting from F, you need go up to get HT

OpenStudy (loser66):

I meant: |dw:1472058016007:dw|

OpenStudy (loser66):

Then move around to get B D N I L for larger one for smaller one, F H T I A

OpenStudy (loser66):

Now, every thing is on scale. You can freely set up the ratio, as long as they are matched up. |dw:1472058151490:dw|

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