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Mathematics
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OpenStudy (tylerballardwildcat):
What is the fourth term of (x + y)8?
medal
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OpenStudy (niksbhalla14mar):
did you get an answer to your earlier question. Please show me too..
OpenStudy (welshfella):
use the same formula in the last question.
OpenStudy (niksbhalla14mar):
Please tell me also.. i couldnt see that question's solution..
OpenStudy (welshfella):
the term will include the value of 8C3
The number of combinations of 3 from 8.
Can you work that out?
OpenStudy (tylerballardwildcat):
im not good with this
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OpenStudy (tylerballardwildcat):
im trying to catch on
OpenStudy (niksbhalla14mar):
How is What is the fourth term of (x + y)8? a question of combination. dint understand it al all... please explain
OpenStudy (owen_turner):
8/3 x^8-3 y^3 = 8!/3! (8-3) x^5 x^3 = 8x7x 6/3x2 x^5 x^3 = 56x^5 y^3
OpenStudy (welshfella):
Ah! I cant remember the details - I'll try and find you a link.
OpenStudy (welshfella):
Owen Turner has the answer
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OpenStudy (niksbhalla14mar):
What did Owen Turner you did ? Have no idea at all...
OpenStudy (owen_turner):
Yes.
OpenStudy (welshfella):
the formula for the (r + 1)th term of (a + b)^n is
nCr a^(n-r) b^r
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