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@ganeshie8 While solving for the shortest distance between two skew lines I came across a method Distance=BA.Unit vector of PQ Where BA is the vector obtained by subtracting starting point of a line with the other and Unit vector of PQ is the normal passing through both lines. How is the method correct? If r1 = a1+tb1, r2=a2+sb2 BA = a1-a2 PQ = b1 x b2/|b1 x b2| { x means cross product }
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@Irishboy123
First consider a "point" and a "line" in 2D : |dw:1472232959307:dw|
Yes I know how to calculate in 2D. Dot product / magnitude of b = a cos theta
Would you agree that the shortest distane between that point to the line is the perpendicular ?
Of course
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|dw:1472233047038:dw|
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