A person removing 2 eggs at time from an Easter basket has 1 left; the person removing them 3 at a time has 2 left; the person removing them 5 at a time has 3 left. What is the fewest number of eggs possible in the basket?
Since we dont know the exact amount of times you can use a variable to change this into an equation. Can you do that?
Honestly I'm not sure what I can do with this problem lol..I googled it and got something where the person made 3 different equations where they use 5k+3, 3n+2 and 2m+1 and those letters used as integers, for my assignment I have to explain the steps for solving this problem and also have the correct answer to receive credit, nice math teacher huh?
haha yeah
anyways the answer the 23 eggs but since you gotta show the steps, try using the equations
Is 23 eggs*
Lol I knew the answer was 23 but my steps for getting that answer is somewhere in the clouds and my words can't seem to pull them down
THey all start out with the same number of eggs?
I'm not sure how many eggs they start with.
hmm Try this: 5 is the largest number and the remaining eggs is 3 so we know It's 5x+3. 3 is the next largest number and the remaining eggs is 2 so we know the answer has got to be odd and the equation is 3y+2. 2, the last number, has a remaining egg of one and the equation is 2z+1.
Can you do the rest from here?
I will certainly try!
oki :P
Not sure if your teacher would take guess work but just in case: 1st person 3 5 7 9 11 13 15 17 19 21 23 25 2nd person 5 8 11 14 17 20 23 3rd person 8 13 23 28 23 is the lowest one that matches all criterias
Thanks so much
No problem :'D
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