Question

What is the equation of the graph below?

A graph shows a parabola that opens up and crosses the x axis near one and a half and four and a half.

y = − (x − 3)2 − 2
y = − (x + 2)2 − 3
y = (x − 3)2 − 2
y = (x + 2)2 − 3

Answer 1

@sleepyjess @samanthagreer

Answer 2

@zzr0ck3r @zepdrix

Answer 3

@rebeccaxhawaii

Answer 4

@pooja195 mind helping?

Answer 5

@.Sam. could u help?

Answer 6

first of all the graph opens upwards so the first coefficient will not be negative.

Answer 7

ok

Answer 8

D

Answer 9

you knocked out all the rest tbh..

Answer 10

Its either C or D
the equation is in vertex form
(x - a)^2 + b where the vertex is at (a,b)

Answer 11

I would go with D, reason being C has a negative downward slope, yet the graph shows it spring back up?

Answer 12

whAT ARE THE COORDINATES OF THE VERTEX ON THE GRAPH?

Answer 13

its like y = 2 and x is somewhere between 3 and 4 from what i see.. but it would be minus 3 i believe..

Answer 14

compare C and D with the standard vertex form and yo#ll get the correct answer

Answer 15

what startles me is
the part where the end meets at minus 2

Answer 16

- that is the vertex

Answer 17

x = 3 and y = -2 at the vertex

Answer 18

so a = 3 and y = -2 fits into the standard form

Answer 19

which is C or D?

Answer 20

* a = 3 and b = -2

Answer 21

b = -2 in the formula

Answer 22

do you follow ?

Answer 23

(x - a)^2 + b

a = 3 and b = -2

Answer 24

just plug the values in

Answer 25

I've given you the answer ...

Answer 26

are you still there?

Answer 27

OK Well I'm not talking to myself anymore.

Answer 28

@welshfella lol I went offline... was bsuy