Question

Check my work mhmmm

Answer 1

Show the following statement is correct using the \(\epsilon\) - \(\delta\) definition of limit.
\[\lim_{x \rightarrow2}(x^2 + x - 1) = 5\]

Answer 2

So, as a reminder, the epsilon delta defintion of a limit

\[ \lim_{x \rightarrow a} f(x) = L\]
\[\forall~\epsilon>0 ~~\exists~\delta>0 \]
Then\[0<|x-a|<\delta \implies |f(x)-L|<\epsilon \]