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On a distant planet a freely falling object has an acceleration of 25 m/s2 . Calculate the vertical distance an object dropped from rest on this planet covers in 1.5 s .
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delta_y = vi*t + 1/2at^2
plug and play.
What is delta_y?
the change in the height
\[\lim_{t \rightarrow 1.5}\frac{ dx }{ dt }\] where x = 1/2at^2 first find the derivative and then plug in t = 1.5 and remember a = 25 m/s^2 since we're on a distant planet and not Earth
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I got 28 m
yep.
That's wrong.
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