Help, i kind of know it but forgot how to do it exactly.
Simplify each expression. Express the answer so that all exponents are positive. Help, i kind of know it but forgot how to do it exactly.
(3x^2/5y^4)^2

Question

Help, i kind of know it but forgot how to do it exactly.
Simplify each  expression. Express the answer so that all exponents are positive. Help, i kind of know it but forgot how to do it exactly.
(3x^2/5y^4)^2

calculusxy · Answer

$$(\frac{3x^2}{5y^2})^2 = \frac{3^2x^4}{5^2y^4} = \frac{9x^4}{25y^4} $$

jwest6894 · Answer

how did u do that first step

calculusxy · Answer

It's called the power rule. It's when you distribute the exponent that is outside of the parenthesis to the terms that are in the parenthesis. Therefore ,I just distributed the 2 to 3 and got $3^2$ and then to $x^2$ to get $x^{2 \times 2} = x^4$. The same thing was done to the denominator too.

calculusxy · Answer

Do you understand it?

jwest6894 · Answer

OK i got it... sorry for late reply.. had to do something, but thanks