Question

Did i Factor this equation the right way?

Answer 1

cannot see the equation

Answer 2

please post all of the question

Answer 3

\[x^{3} -8 / 25x - 4x^2 \times 10x +4x/2x^2-9x +10\]

Answer 4

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Answer 5

Ok so first i simplify

x^3 - 8... (x-2)(x^2 + 2x + 4)

Answer 6

[(x^3−8)/(25x−4x^2)]×[(10x+4x)/(2x^2−9x+10)] im suppose to factor .. dont think im suppose to combine like terms just yet.

Answer 7

x^3 - 8 = (x-2)(x^2 + 2x + 4) correct?

Answer 8

^ yes that is correct

Answer 9

(x^2 + 2x + 4) how would i factor

Answer 10

because i dont think it can be factored.

Answer 11

the question is ambiguous - it can be read in different ways

is it

x^3 - 8 10x + 4x
----------- * ----------
25x - 4x^2 2x^2 - 9x + 10

Answer 12

yes

Answer 13

use fractions or parentheses with these complicated expressions otherwise its confusing

Answer 14

i tried [(x^3−8)/(25x−4x^2)]×[(10x+4x)/(2x^2−9x+10)]

Answer 15

right - same as mine.

Answer 16

(x^2 + 2x + 4) so can i factor this?

Answer 17

no

Answer 18

2x^2 - 9x + 10 can be factored though
it is (2x - 5)(x - 2)

Answer 19

then the x-2 will cancel out with the x - 2 from the factors of x^3 - 8

Answer 20

so we have
x^2 + 2x + 4 14x
------------- * ---------
25x - 4x^2 2x - 5

Answer 21

didnt think so..

(x-2)(x^2 + 2x + 4) 10x + 4x
----------- * ----------
25x - 4x^2 2x^2 - 9x + 10


so 25x-4x^2 = x(4x - 25) or would i use the formula?

Answer 22

x(25 - 4x) is correct

Answer 23

(not suppose to be 10x btw) 10 + 4x = 2(5 + 2x) ?
2x^2-9x+10 you use the ac method and get...

Answer 24

(2x - 5)(x - 2)

Answer 25

^thats for 2x^2 - 9x + 10?

Answer 26

yes

Answer 27

how did u get that

Answer 28

using the ac method 2 * 10 = 20 and 20 = -5 * -4 :-

2x^2 - 9x + 10
= 2x^2 - 4x - 5x + 10
= 2x (x - 2) - 5(x - 2)
= (2x - 5)(x - 2)

Answer 29

hm..

Answer 30

dont agree?

Answer 31

well i thought

Answer 32

you thought you'd be able to cancel

Pity the top is not 4x - 10 !!

Answer 33

2x^2 - 9x + 10

u do 2 time 10 which equals 20..

Now what can i add to get -9 that i can multiply to get 20?

-5 and -4.. so wouldnt it just be (x - 5) (x - 4) ?

Answer 34

the x-2 cancles though

Answer 35

No - because we have 2x^2

Answer 36

and the last 2 numbers in each bracket have to make + 10.

Answer 37

you use -4x and -5x to give the -9x

Answer 38

man factoring is hard...

Answer 39

everytime i think i got it i dont

Answer 40

yea factoring trinomials with x^2 is not so difficult but when you have a number > 1 before the x^2 its more complicated

Answer 41

this should help you

http://openstudy.com/users/welshfella#/updates/55c0a151e4b01850ec7ff57d

Answer 42

using the ac method 2 * 10 = 20 and 20 = -5 * -4 :-

2x^2 - 9x + 10
= 2x^2 - 4x - 5x + 10
= 2x (x - 2) - 5(x - 2)
= (2x - 5)(x - 2)

So hmmm so for the ac method.. u multiply the 2 times 10.. get 20 u ask wha tcan u multiply to get 20 that i can add to get to -9.. -5 + -4 sooo
= 2x^2 - 4x - 5x + 10
you take 2x from those to get 2x(x - 2) and you take 5 from those and get 5(x -2) .. ok

so can i do it like this if i wantd to?

= 2x^2 - 5x - 4x + 10? if not why?

Answer 43

like what order do i put that in -4 first or -5

Answer 44

yse the -5x and -4x may be written in that order but you are lookng for factors - you cant facor 2x^2 - 5x so you swapp them around and then you can factor.

Answer 45

oh ok.....

Answer 46

if you look at the link you'll see a similar situation where I first wrote tye middle terms in the wrong order

Answer 47

after working out the ac = 20 you can then write it in prime factor form as in the link. I junped a step here - i just went straight to -4 and -5 because they give me the -9x

Answer 48

oh ok

Answer 49

so if i were to have a test on factoring.. what formulas would i need.

Answer 50

a^2 - b^2 = (a + b)(a - b)

the formulas for a^3 - b^3 and a^3 + b^3 would also be useful.

Answer 51

i have ax^3 +b^2 + cx + d = a/b = c/d
a^3 + b^3 = (a + b)(a^2-(ab)+b^2)
a^3 - b^3 = (a - b)(a^2+(ab)+b^2)
a^2 - b^2 = (a-b)(a

Answer 52

a^2 - b^2 = (a-b)(a+b)

Answer 53

for the trinomials you need practice

Answer 54

a trinomial has 3 numbers right?

Answer 55

Yes 3 terms try the following
x^2 + 5x + 4

x^2 - x - 6

2x^2 - 5x - 2

Answer 56

sorry the last one should be

2x^2 - 5x + 2

Answer 57

gotta go
good luck