Question

needing precal help! see attachment

Answer 1

@Wholock so i'm guessing you subtract them now?

Answer 2

Yep, and don't let the denominator confuse you, since they have a common denominator, you just have to focus on the numerator.

(2x + 6) - (sqrt(x) - 8)

Answer 3

\[2(x+3)-\sqrt{x-8}\]

Answer 4

No, don't pull out the 2.

Use the distributive property on the second part of the equation
\[2x + 8 - \sqrt{x} + 8\]

Answer 5

Look at the problem, the square root only covers the x, not the 8.

Answer 6

Oh! forgive me, change that first + 8 to a +6!

Answer 7

\[2x + 6 - \sqrt{x} + 8\]

Answer 8

okay so now it would be \[2x-\sqrt{x}+14\]

Answer 9

over 3x

Answer 10

Yes!

Answer 11

awesome, i have 3 more! :')

Answer 12

Okie-dokie