If (7^2)^x = 1, what is the value of x? Explain your answer. If (7^0)^x = 1, what are the possible values of x? Explain your answer.
What's 7*7?
49
You may rewrite it as (49)^x = 1.
w8 is that for the first one
Yes.
shouldn't it be 7 times 2 or no?
Do you know what exponent always makes the numerical value as 1 for the result?
You wrote 7^2?
That's 7 to the power of 2. Which means (7)*(7) = 49.
ohhh omg im so dumb -.-
ok so the answer would be 1 for the first correct
Take a step back.
If the exponent is 0, the value becomes 1.
If x was 1, it would be 49^1 = 49.
49 does not equal 1, sorry.
so w8 sorry im not good at this, the answer would be....49^1 = 49 or (49)^x = 1
Here, let me rewrite it: (7^2)^x = 1 Your GOAL is to find what the x value is which is an exponent in this case (49)^x = 1 If x = 1 (49)^1 = 1 49 does not = 1. if x = 0 (49)^0 = 1 1 = 1 Anything to the exponent of 1 equals 1.
Anything to the exponent of 0 equals 1, sorry for the typo.
ok i get it now thx! could u also help me with the second one?
Yes, of course, this one is actually cute, if I must say so myself.
lol ur a lifesaver i swear
(7^0)^x = 1 They try to trick you in a sense.
(7^0)^x = 1 7^0 already equals 1. (1)^x = 1. There is two values which allow this to equal one, can you guess the two values, or do you need me to explain it further?
sorry i dont know :/ would it be one of them be 0?
No, don't feel discouraged, you're fine. Yes, one would be 0, good job. (1)^0 = 1. 1 = 1. (:
Anything to the first power is the same numerical value. (1)^1 = 1 1 = 1 1*1 = 1. Just like when I stated (49)^1 = 49 49 * 1 = 49.
ohh ok so it would be 0 and 1 right
Yes, correct.
thank you soo much!
Anytime!
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