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3^2 + (7 − 2) ⋅ 4 − 6 over 3.
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Is this what you mean? @kikilandry \[\frac{ 3^2 + (7 − 2) ⋅ 4 − 6 }{ 3 }\]
i didnt post this
\[3^2+ (7-2)\times 4- \frac{ 6 }{ 3}\]
lmao always blaming michael for stuff
@kikilandry so you got your own answer, or you need help with it?
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i need help with it
Sure. \[9+(7−2)(4)-\frac{ 6 }{ 3 }\] \[9+(5)(4)−\frac{ 6 }{ 3 }\] \[9+20−\frac{ 6 }{ 3 }\] \[29−\frac{ 6 }{ 3 }\] \[29−2 =27\]
thank you so much!
You welcome hun
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