how do i subtract two powers...

for example 4^8-8

both 8s are powers

Question

how do i subtract two powers...

for example 4^8-8

both 8s are powers

saadsword · Answer

4^(8-8)= 4^(0)= 1

akimi · Answer

wow its that simple thanks i wasnt sure

saadsword · Answer

no problem

akimi · Answer

so if $$16\times2^{m}=4^{8-8}$$ would m equal $$\sqrt{7.5}$$

jhonyy9 · Answer

what is there please 16 time 2^m = ?

akimi · Answer

im solving for M

akimi · Answer

the question was

If n = 8 and 16 • 2m = 4n – 8, then m =

jhonyy9 · Answer

on the right side 4^8-8 = 4^0 = 1 

so from this result 

16*2^m = 1

ohhh than there are 

16*2^m = 4^n -8 here in the right side just n is the exponent of 4 ?

jhonyy9 · Answer

ok. i understand that this is your question but from there just m is the power of 2 or n is exponent too ?

jhonyy9 · Answer

16 = 2^4

2^4 *2^m = 2^(4+m)   this is for left side 

but what is exactly on the right side ?

jhonyy9 · Answer

on the right side n is exponent same with m on the left side ?

akimi · Answer

when you plug $$n=8$$ in the right side $$4^{n-8}$$ you get 1 after that they ask you to solve $$m$$ which is $$16\times2^{m}$$ it ends up being $$16\times2^{m}=1$$

leonhard_euler · Answer

$$4^{8-8}
 = 4^{8}\times4^{-8}
 = \frac{ 4^{8} }{ 4^{8} }
  = 1$$