Question

I have 2 points on a parabola 7,-10/6 and 8, -30/6 plus I have the y value of the vertex = 1. I am supposed to find the x intercepts but am stumped

Answer 1

do you have the equation?

Answer 2

no, that is the problem. I need to develop the equation from the information given

Answer 3

one second this might take a while

Answer 4

you would be my hero

Answer 5

I think it is something along the lines of:
y=ax^2+bx+c
-10/6=a(7)^2+b(7)+c and -30/6=a(8)^2+b(8)+c
then maybe you can try to find a relationship between the two equations and make them equal to each other.
As of right now, im still thinking

Answer 6

I have looked at it numerous ways. As a vertex form it becomes:
-10/6=a(7-h)^2 + 1 and -30/6=a(8-h)^2 +1 so 2 equations with 2 unknowns but the solution is incredibly unwieldy. Is that perhaps the only solution?

Answer 7

ill leave for now and try to work this out on my note book, it is easier that way. ill be back

Answer 8

thanks I will check back

Answer 9

why the strange y values ? isn't -30/6 just -5 ?
and -10/6 is -5/3

Answer 10

I don't know...is there a clue in there somewhere

Answer 11

I don't see any clue. This is tough, because it is non-linear
also, there are different answers
I can see drawing two different parabolas