Question

HELP ME, RIP.How many solutions does this linear system have?

y =2/3 x+ 2

6x – 4y = –10

one solution: (–0.6, –1.6)
one solution: (–0.6, 1.6)
no solution
infinite number of solutions

Answer 1

What do you think?

Answer 2

Don't I need to solve y= 2/3x+2

Answer 3

you need to solve for x or y. Take that equation and plug into other equation to solve for either x or y.

Answer 4

y = 2/3x + 2

6*x - 4(2/3x + 2) = -1 solve for x. Then take that value sand plug into equatin to solve for y.

Answer 5

not -1, suppose to be -10.

Answer 6

Then you will have your solution.

Answer 7

6*x - 4(2/3x + 2) = -1 and when I get that answer I plug it into y

Answer 8

No, you are solving for x, you plug the x value into one of the equations to solve for y.

Answer 9

y = 2/3x + 2 doesn't need to be solved. I mean you could solve for x, but you are just doing more work than needed. This equation is solved for y. Sub. the equation here in for the y into the other equation. When doing this we have one equation in terms of x. Now you can solve for x.