Question

Two planes left the same airport at the same time traveling in opposite directions. The first plane traveled at an average rate of 30 mph slower than the second plane. After 3 hours, the planes were 3150 miles apart.

Enter an equation that can be used to determine when the planes are 3150 miles apart, where x represents the average rate of the second plane.

Enter the average rate of change of the slower plane

Answer 1

@jim_thompson5910

Answer 2

how far did you get with this?

Answer 3

no where

Answer 4

idk where to start

Answer 5

which plane is traveling faster? the first or second?

Answer 6

second

Answer 7

`The first plane traveled at an average rate of 30 mph slower than the second plane`
`x represents the average rate of the second plane`

speed of first plane = x-30
speed of second plane = x

do you agree?

Answer 8

yes

Answer 9

if the speed of the second plane is x and it travels for 3 hours, then what distance does it travel in terms of x?

Answer 10

hint:
distance = speed*time

Answer 11

x+30?

Answer 12

second plane
distance = unknown
speed = x
time = 3


distance = speed*time
distance = x*3
distance = 3x

make sense?

Answer 13

yes

Answer 14

what is the distance for the first plane?

Answer 15

x-30

Answer 16

that's the speed

Answer 17

it travels for 3 hours

what is the distance?

Answer 18

-30 x 3 = -90

Answer 19

first plane
distance = unknown
speed = x-30
time = 3


distance = speed*time
distance = (x-30)*3
distance = 3x-90

make sense?

Answer 20

yes

Answer 21

(distance of first plane) + (distance of second plane) = total distance

(3x) + (3x - 90) = 3150

3x + 3x - 90 = 3150

6x - 90 = 3150

I'll let you solve for x

Answer 22

39.93

Answer 23

6x - 90 = 3150
-6 -6
----------------
x - 90 = 3144

90/90
3144/90 (39.93)

Answer 24

is that it?

Answer 25

6x - 90 = 3150

6x - 90+90 = 3150+90 .... add 90 to both sides

6x = 3240

x = ???

Answer 26

540

Answer 27

yes x = 540

Answer 28

so x-30 = 540-30 = 510

Answer 29

how do i put it into an equation?

Answer 30

speed of first plane = 510 mph
speed of second plane = 540 mph

Answer 31

so the average rate of change is 30mph?

Answer 32

speed = average rate of change

Answer 33

oh okay

Answer 34

how do i put it into an equation?

Answer 35

we just solved the equation above

Answer 36

yes but i have to answer it in an equation

Answer 37

Enter an equation that can be used to determine when the planes are 3150 miles apart, where x represents the average rate of the second plane.

Answer 38

the equation is shown above

Answer 39

this? x-30 = 540-30 = 510

Answer 40

no

Answer 41

the first equation I wrote out

Answer 42

x = 540

Answer 43

scroll up more

Answer 44

6x - 90 = 3150

6x - 90+90 = 3150+90 .... add 90 to both sides

6x = 3240

x = ???

Answer 45

they're probably looking for 6x-90 = 3150 or 3x+3x-90 = 3150

Answer 46

thats my guess.
ok thanks again jim

Answer 47

no problem