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Mathematics 19 Online
OpenStudy (aaaaaaaaaaaaaa):

Jaz was 43 inches tall. Eighteen months later she was 52 inches tall. find the constant rate of change for Jaz's height

OpenStudy (carlyxphan):

Ok so to solve this you need to make an equation right? So because she is 43in already it would be 43+x=53. Does that help?

OpenStudy (carlyxphan):

*** 43+x=52

OpenStudy (wckeller):

You can solve this problem by using the slope formula. \[m=\frac{ y_2 -y_1 }{ x_2-x_1 }\] Use the two heights and times as points on a graph. (0,43) (18,52) Plug in the numbers: \[m=\frac{ 52 -43 }{ 18-0 }\] \[m=\frac{ 9}{ 18 }\] \[m=\frac{ 1}{ 2}\] The constant rate of change for Jaz's height is: 0.5inches per month

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