I've got 5 questions that I absolutely cannot solve. I'm fairly new to logs. If anyone could help me with very detailed answers, that'd be awesome!
P.S. Sorry for the weird formatting. Trying to make it Wolfram Alpha friendly.

Simplify:
1) [(8a)^(-1/3) x b^(3/2)]/[a^(5/3) x b^(-1/2)]
Rationalize the denominator, then simplify:
2) (18)/(4+sqrt(7)) -5sqrt(7)
Solve:
3) [(5^x^2)/(125)] = 25^x
4) ln(1-x) + ln(2-x) = ln(x+14)
Expand the following expression. (Assume all variables are positive and e is the base for the natural exponential.):
5) ln[((8e^2)(x^5))/((x^2+1)(^3sqrt(x+2)))]

Question

I've got 5 questions that I absolutely cannot solve. I'm fairly new to logs. If anyone could help me with very detailed answers, that'd be awesome! 
P.S. Sorry for the weird formatting. Trying to make it Wolfram Alpha friendly.

Simplify:
1) [(8a)^(-1/3) x b^(3/2)]/[a^(5/3) x b^(-1/2)]
Rationalize the denominator, then simplify:
2) (18)/(4+sqrt(7)) -5sqrt(7)
Solve:
3) [(5^x^2)/(125)] = 25^x
4) ln(1-x) + ln(2-x) = ln(x+14)
Expand the following expression. (Assume all variables are positive and e is the base for the natural exponential.):
5) ln[((8e^2)(x^5))/((x^2+1)(^3sqrt(x+2)))]

loser66 · Answer

$$\dfrac{8a^{-1/3}b^{3/2}}{a^{5/3}b^{-1/2}}$$

right?

wgwiii · Answer

@Loser66 Yes. I think I've got that one solved. I got b^2/2a^2