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precal help: see attachment!
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Beautiful question at last
oh wow, thats hard
with what i know i would say b
yes I also think it's b
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\[f(x) = (x - 1)^2 - 4\] To make it easier when solving for inverse thingy change f(x) to y and then switch x and y and solve for y. See the following \[y = (x - 1)^2 - 4\] and now switch the x and y and solve for y \[x = (y-1)^2 - 4\] add 4 to both ssides \[x + 4 = (y-1)^2\] now apply sqrt to both sides to get rid of the ^2 \[\sqrt{x+4} = y-1\] add 1 to both sides \[1+ \sqrt{x + 4} = f(x)^-1\]
yes yes it is B you got it right but i had to waste my time don't blame me am so bored lol
:)))) nicely explained good job :)
Lol Thanks if you have more questions just tag me
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