Question

MEDAL PLEASE HELP CHECK ANSWERS
http://prnt.sc/cit9zn

Answer 1

@Ellie201 @TheGirlGenius @thefluffmuncher @imqwerty @Awolflover1 @AloneS @kittiwitti1 @ltrout @Conqueror

Answer 2

Already answered this. Use the PEMDAS and exponential rules.
http://www.mathsisfun.com/algebra/exponent-laws.html

Answer 3

sorry but i have been trying to get help for such a long time now...i just need someone to check my answers and no one will

Answer 4

i have more than this...i just need someone to check what i already have

Answer 5

We are not your answering key. Please check yourself.

We can walk you through any steps if you want to see if you did anything wrong, but we are not an automated solutions manual.

Answer 6

but barely anyone ever helps so i have to try and figure it our my self and now i just want someone to check my answers but no one can do that either

Answer 7

Tell me what steps you went through and I'll tell you if you messed up anywhere.

Answer 8

can you just tell me if they are wrong or right it will be much quicker... i have been doing this for hours now and i just really want to be done:(

Answer 9

... maybe @agent0smith can help idk

Answer 10

hes not even online:/

Answer 11

I'll give you two hints. There are two types of exponentials in this equation: \(3^{x}\) and \(4^{x}\) (the \(x\) is just some random variable). So you can divide anything with base 3 by something else with base 3, same for the base 4.

Here is the exponent rule for multiplying and dividing:\[a^{x}\times a^{y}=a^{x\times y}\]\[\frac{b^{x}}{b^{y}}=b^{x-y}\]

Answer 12

So you can simplify the two values with base 3, and combine the values of the base 4's.

that's all I can tell you. Sorry.

Answer 13

I wasn't online.

Answer 14

Oh.


Okay