Quadrilateral OPQR is inscribed inside a circle as shown below. What is the measure of angle Q? You must show all work and calculations to receive credit.
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OpenStudy (danieldjpon3):
kk
OpenStudy (danieldjpon3):
Can you send the attachment please
OpenStudy (danieldjpon3):
kk brb ima help this kid out real fast
OpenStudy (danieldjpon3):
I'm back
OpenStudy (danieldjpon3):
@harmabe91113
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OpenStudy (harmabe91113):
cool
OpenStudy (danieldjpon3):
kk
OpenStudy (danieldjpon3):
im gonna try and solve it
OpenStudy (sshayer):
in a cyclic quadrilateral sum of opposite angles=180
OpenStudy (harmabe91113):
ok thanks
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OpenStudy (sshayer):
yw
OpenStudy (danieldjpon3):
92 is teh answer
OpenStudy (danieldjpon3):
And I'll send you my work
OpenStudy (danieldjpon3):
opposite pairs of angles of an inscribed quadrilateral add to 180°
O + Q = 180°
2x + 2x + 4 = 180°
OpenStudy (danieldjpon3):
solve for x then substitute into 2x + 4 to get Q
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OpenStudy (danieldjpon3):
2x + 2x + 4 = 180
OpenStudy (danieldjpon3):
^ that's the equation you need to solve for x
OpenStudy (danieldjpon3):
After combining you have
4x + 4 = 180
Subtract 4 from both sides
OpenStudy (danieldjpon3):
on the right side left with 174 and on the left we have x
OpenStudy (sshayer):
correct.
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OpenStudy (danieldjpon3):
176*
OpenStudy (danieldjpon3):
srry
OpenStudy (danieldjpon3):
so 4x = 176
divide by 4
OpenStudy (harmabe91113):
44
OpenStudy (danieldjpon3):
4x minus 4 is x
180 minus 4 is 176 in other words
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OpenStudy (danieldjpon3):
ya 44
OpenStudy (danieldjpon3):
2x + 4, so plug in 44 for x to get
Q = 2(44) + 4
OpenStudy (danieldjpon3):
Q = 2x + 4, so plug in 44 for x to get
Q = 2(44) + 4
OpenStudy (danieldjpon3):
srry
OpenStudy (danieldjpon3):
this last one is correct
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OpenStudy (danieldjpon3):
and u get 92
OpenStudy (danieldjpon3):
and that's the asnwer
OpenStudy (danieldjpon3):
yup
OpenStudy (danieldjpon3):
ok medal pls
OpenStudy (danieldjpon3):
:D
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