PLEASE HELP!
Which is the equation for the line perpendicular to y = -(5/3)x + 6 and containing P(-2, 3)?
a. y - 2 = -(3/5)(x - 3)
b. y = -(5/3)x + 13/3
c. y = -(3/5)x + 21/5
d. y = (3/5)x + 21/5

Question

wckeller · Answer

A line that is perpindicular to y=-(5/3)x+6 will be the line that has a reciprocal slope.
Even though this problem needs the point (-2,3) to be in the line, we can use the process of elimination to find the answer.

First find the recirocal of -(5/3)

wckeller · Answer

reciprocal**

jiteshmeghwal9 · Answer

The line perpendicular to the line ax+by+c=0 is ax-by+c'=0.

wckeller · Answer

Hint: The reciprocal of a fraction will have the opposite sign, and will be flipped

jiteshmeghwal9 · Answer

Given is the line 5x+3y-18=0

So the eqn for perpendicular line should be 5x-3y+c'=0

jiteshmeghwal9 · Answer

As the perpendicular line passes through point (-2,3)

So replace x by -2 and y by 3 to get c'.

jiteshmeghwal9 · Answer

Do you know the equation now?