Find m
|dw:1474162962264:dw|
BD bisects ABC
Since BD bisects the angle, both half are equal angles... 4x^2 - 10 = 7x + 5
if you put that into the standard form... ax^2 + bx + c = 0 , you can use the quadratic formula to solve for the value(s) of x. 4x^2 - 7x - 15 = 0
sorry i posed the wrong question how do i solve for ABC with an x^2 and x
once you figure out x... then you know both those angle measures... 7x + 5 and 4x^2 - 10
ok i get it forgot about the quadratic formula
yeh, if you solve ax^2 + bx + c = 0 for x=.. then you get \[x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
so will there be two answers?
@DanJS i'm stuck again sorry how would I solve for x using the quadratic equations since there are two answers?
right, what answers did you get
3 and -1.25
yeah you got it, in this case, a negative angle measure would not make sense, the -1.25 gives 7x + 5 = 7*-1.25 + 5 negative angles.
that's what I thought but wasn't sure thanks a lot @DanJS
welcome
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