Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (sen_turtle):

Find m

OpenStudy (sen_turtle):

|dw:1474162962264:dw|

OpenStudy (sen_turtle):

BD bisects ABC

OpenStudy (danjs):

Since BD bisects the angle, both half are equal angles... 4x^2 - 10 = 7x + 5

OpenStudy (danjs):

if you put that into the standard form... ax^2 + bx + c = 0 , you can use the quadratic formula to solve for the value(s) of x. 4x^2 - 7x - 15 = 0

OpenStudy (sen_turtle):

sorry i posed the wrong question how do i solve for ABC with an x^2 and x

OpenStudy (danjs):

once you figure out x... then you know both those angle measures... 7x + 5 and 4x^2 - 10

OpenStudy (sen_turtle):

ok i get it forgot about the quadratic formula

OpenStudy (danjs):

yeh, if you solve ax^2 + bx + c = 0 for x=.. then you get \[x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

OpenStudy (sen_turtle):

so will there be two answers?

OpenStudy (sen_turtle):

@DanJS i'm stuck again sorry how would I solve for x using the quadratic equations since there are two answers?

OpenStudy (danjs):

right, what answers did you get

OpenStudy (sen_turtle):

3 and -1.25

OpenStudy (danjs):

yeah you got it, in this case, a negative angle measure would not make sense, the -1.25 gives 7x + 5 = 7*-1.25 + 5 negative angles.

OpenStudy (sen_turtle):

that's what I thought but wasn't sure thanks a lot @DanJS

OpenStudy (danjs):

welcome

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!