Use your calculator to solve the equation sin(x) - ln(x) = 0 over the interval [0, infinity). Make sure you're in radians. I started by doing sin(x) = ln(x), then I said e^(sin(x)) = x. But I wasn't sure how to get x outside of the sin part. Could I get some hints? Thanks so much in advance!
@TheSmartOne please your opinion about this ? i think i can agree it and you ?
message a qualified helper!!!
ur in luck bc there is one online rn
well there WAS one...nm
well a simple solution is graph both curves and looks for points of intersection... and that will give you a good starting point as to what values of x to try
I think you'll find there is only one point of intersection... you can use this site to graph them easily https://www.desmos.com/calculator
Thank you!
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