Graph the image of the given triangle, rotated 90° counterclockwise about the origin. http://prntscr.com/ckfpou Is this correct?
@IrishBoy123
Mmmmm
@Loser66
Hmmm... If the blue triangle is the preimage (in the second quadrant), then the image should be in the third quadrant, since it is rotated counter-clockwise about the origin. The rule of rotation is: \(R_{-90}: (x,y) -> (-y,x)\) Example: A preimage (-3,6) would have x=-3, y=6, its image would be at (-6,-3), i.e. rotated from the second quadrant to the third quadrant.
the blue triangle is the image
It's the same principle. If the grey is the preimage, and since the preimage straddles on the x-axis, a 90\(\deg\) counterclockwise rotation should bring it to straddle the +y-axis. The transformation relation does not change.
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