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Solve for a. 4(a + 3)=12 + 4a4(a + 3)=12 + 4a no solution all real numbers −3−3 −1
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Alright before we can bring all the a's to one side, you have to distribute the brackets, what is \[4(a+3)\]distributed?
4a+12
Yes
Correct!
Exactly so now we have \[4a+12=12+4a\]What do you think is up next?
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comb like terms?
*combine
Yep, something weird happens when you try to do that though, right?
Let's combine like terms, how do you bring the 4a to one side?
subtract right
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Yes, so we have \[4a-4a+12=12+4a-4a\], and the 4a's cancel! So do the 12's! there is no solution.
THANKS KOOKIE BTS FOR LIFE
lol
can you help me with another one
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