If pressure is applied to a rock until it's volume is reduced by half, how does its new density compare to it's original density.
1. Its half of its original density
2.It is twice of it's original density
3.It is the same as its original density
4.It is one-third its original density.

I think its B but please explain!

Question

If pressure is applied to a rock until it's volume is reduced by half, how does its new density compare to it's original density. 
1. Its half of its original density
2.It is twice of it's original density
3.It is the same as its original density
4.It is one-third its original density. 

I think its B but please explain!

romancelanguages · Answer

@pooja195 @Luigi0210 @sammixboo @Awolflover1 @inkyvoyd

legomyego180 · Answer

Ideal Gas Law:
$$PV=nRT$$
Modified for density:
$$d=m/v$$
$$d=\frac{ P*MW }{ RT}$$
Where:
MW = Molecular Weight
d=density
P=pressure
R=ideal gas constant
T=Temperature

This should help you out

romancelanguages · Answer

Haha its sort of confusing me more