Write the equation of the quadratic function with roots -9 and and -3 and a vertex at (-6, -1).

Question

retireed · Answer

Okay, I figured it out, I think.

In order to get the roots, you need to use

     (x+9)(x+3) = 0        which is x^2 + 12x + 27 = 0

That quadratic equation yields a vertex at -6, -9

in order to get the vertex to be at -6, -1.  I had to divide the equation by 9.

          (x+9)(x+3)/9 = 0       Plot it on a graphing calculator.

hiyathere_20 · Answer

okay how do I plot on a graphing calculator

hiyathere_20 · Answer

I got 3 I multiplied 9*3 and got 27 and divided that by 9 and got 3.

retireed · Answer

demos.com/calculator

it looks like this... attached file

hiyathere_20 · Answer

okay so would it be 3x^2