Mathematics
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OpenStudy (asdfghj8):
Solve the system of equations. *Will Medal*
-5x+4y=-8
-9x+5y=1
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OpenStudy (jango_in_dtown):
Method of cross multiplication is known to you?
OpenStudy (asdfghj8):
yes but isnt that just used for fractions? I know for this we have to eliminate one of the variables...
OpenStudy (jango_in_dtown):
well you can use one of the methods: 1st method:
from the first equation find x in terms of y and then substitute this x value in the second equation
OpenStudy (jango_in_dtown):
then you will get a value of y..
OpenStudy (asdfghj8):
can you show me how to do that? every time i try i get it wrong
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OpenStudy (jango_in_dtown):
Ok sure
OpenStudy (jango_in_dtown):
1st equation :
-5x+4y=-8
so 5x=4y+8 implies x=(4/5)(y+2).
OpenStudy (jango_in_dtown):
wait.. lets do it in an easier way
OpenStudy (asdfghj8):
ok
OpenStudy (jango_in_dtown):
I am giving you a general rule for one step solution
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OpenStudy (jango_in_dtown):
Suppose you have the following equations:
ax+by+c=0
dx+ey+f=0
OpenStudy (jango_in_dtown):
then x/(bf-ec)=y/(cd-af)=1/(ae-db)
OpenStudy (asdfghj8):
ok
OpenStudy (jango_in_dtown):
first put the given equations in that form as I said
OpenStudy (jango_in_dtown):
then you have
-5x+4y+8=0
-9x+5y-1=0
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OpenStudy (asdfghj8):
i see that
OpenStudy (jango_in_dtown):
then use the general formula
x/(-4-40)=y/(-72-5)=1/(-25+36)
OpenStudy (asdfghj8):
alrright
OpenStudy (jango_in_dtown):
so x=(-44/11)=-4
y=(-77/11)=-7
OpenStudy (asdfghj8):
so why dividing by 11?
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OpenStudy (jango_in_dtown):
see what er did...
check the coefficients
a b c
d e f
OpenStudy (asdfghj8):
ohhhhhhh ok
OpenStudy (jango_in_dtown):
|dw:1474639581429:dw|
OpenStudy (jango_in_dtown):
for y , omit the second column and do the same thing.