Help
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Thank you anyway :)
this 4x^2 -16 is difference of two squares do you know formula of this ?
2x^2 +10x +12 = what can you factorizing out from these every terms ?
I figured it out I believe I ended up with 2x^4 + 3/ 1x^3 - 4
ok i like help you step by step please answer my posted questions and will get sure the right answer
1x^2 + 5x + 6
fo 4x^2 -16 = 4(x^2 -4) = ? x^2 -4 = use a^2 -b^2 = (a-b)(a+b)
so there above wrote x^2 +5x +6 this has a 2 in front again ,yes ?
will be 2(x^2 +5x +6) = 2(x*x +(2x+3x) +2*3 = you can factorizing completly
Kitty do you see it how ?
this x^2 +5x +6 = x*x +2x +3x +2*3 = x(x+2) +3(x+2) = ?
factorize out the (x+2) and will get = (x+2)(x+3) but dont forgot the 2 from the front of these all
so this is clearly ?
what about this fo 4x^2 -16 = 4(x^2 -4) = ? x^2 -4 = use a^2 -b^2 = (a-b)(a+b)
Kitty please collaborate bc. is opposite to OS rules to give directly right answers
just dm her the answer lol
@TheSmartOne
Sorry, was on the phone with my teacher
what grade you in?
ok. so please collaborate Kitty , wait
I am in 12th grade but this is a class from 11th grade I never finished
ohhhhhhhh
fo 4x^2 -16 = 4(x^2 -4) = ? x^2 -4 = use a^2 -b^2 = (a-b)(a+b)
Wouldn't you factor it so it would be 4x^2 - 16
so than you factorize out the 4 and factor it will can simplify more easy what will be possible
Kitty how you divide two fractions ?
Kitty you dont know it ?
multiplie the first by second inversed
sshayer your opinion about this ?
x + 3 ---------- 4x^2 - 16 ----------------- = ? 2x - 4 ----------------- 2x^2 + 10x + 12
x +3 2x^2 +10x + 12 ----------- * ------------------- = ? 4x^2 - 16 2x -4
\[\frac{ x+3 }{ 4 x^2-16 }\times \frac{ 2x^2+10 x+12 }{ 2x-4 }=\frac{(x+3)2(x^2+5x+6) }{ 4(x^2-4)2(x-2) }\]
now cancel 2 and make factors and see if you can cancel any factor
but you can factorizing again completly the x^2 +5x +6 = ?
and x^2 -4 = (x-2)(x+2) yes ?
sshayer ??? x^2 +5x + 6 = (---)(---) ???
\[x^2+2x+3x+6=x(x+2)+3(x+2)=(x+2)(x+3)\]
yes sure this is easy
Kitty do you understand these ?
I don't but my teacher is about to call to check my answers
\[=\frac{ \left( x+3 \right)\left( x+2 \right)\left( x+3 \right) }{ 4(x+2)(x-2)(x-2) }=\frac{ \left( x+3 \right)^2 }{ 4\left( x-2 \right)^2 }\]
Thank you guys so much I got a 4/5 on my test I know I didn't really understand it but I appreciated the help
let me know where you don't understand.
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