Find three consecutive odd integers such that their sum is five more than four times the largest integer.
Yeah convert english to math is what is being taught here. three consecutive odd numbers means they come in order, (3,5,7) so let's say the first number is o we have o, o+2, and o+4 (if o = 3, then 3+2 = 5, 3+4 = 7, it's every other number) "their sum is fire more than four times the largest integer" so, what's the largest integer??? o+4 right? their sum is o + o+2 + o+4 = 3o+6 so (3o+6) is five more than four times (o+4) (3o+6) = 5 + 4(o+4) solve for o
you can write the 3 odd integers as 2x+1 , 2x + 3 and 2x + 5
oh I see, so instead of writing o, which gives the possibility that o can be even you write 2x+1 to make sure it's odd! good catch
yes
In the book, I am getting the answers of -15, -13, and -11 clearly confused.
2x + 1 + 2x + 3 + 2x + 5 = 4(2x + 5)+ 5
6x + 9 =8x + 25 -16 = 2x x = -8 so first number = 2(-8) + 1 = -15
Thank you very much @welshfella , and @LannyXX!
yeah!
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