Question

@WIll.H

Answer 1

the length of the tangents from a common point is always equal

Answer 2

AB=AF
CB=CD
EF=ED

PERIMETER OF TRIANGLE 'AEC' = AB+BC+CD+DE+EF+AF

Answer 3

ok

Answer 4

@Kevin

Answer 5

i have to go
KEvin will help and @jiteshmeghwal9 is right but there's easier way

Answer 6

ok

Answer 7

Where will u go @Will.H ?

Answer 8

gt the answer ?

Answer 9

No, I am still trying to figure out.

Answer 10

AB=AF
CB=CD
EF=ED

PERIMETER OF TRIANGLE 'AEC' = AB+BC+CD+DE+EF+AF
perimeter=2(AB+CD+FE)

Answer 11

now can u figure it out ?

Answer 12

How do you know about this jitesh ?
AB=AF
CB=CD
EF=ED

Answer 13

the length of the tangents from a common point is always equal

Answer 14

I mean why you think AB = AF etc

Answer 15

Sorry, I still don't understand. hehe..

Answer 16

It always like this ?
I mean for all of circle in triangle

Answer 17

u mean?

Answer 18

I mean u r right

Answer 19

thx

Answer 20

6.5 + 6.5 + 8 + 8 + 22.5 + 22.5 = 74

Answer 21

is that correct?

Answer 22

right

Answer 23

You are awesome @NvidiaIntely :D

Answer 24

Thanks Jitesh!

Answer 25

yw