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Mathematics
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zarkam21 (zarkam21):
Just checking
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zarkam21 (zarkam21):
@welshfella
zarkam21 (zarkam21):
I just need to bother you for a sec with this question can you check it over
zarkam21 (zarkam21):
zarkam21 (zarkam21):
OpenStudy (welshfella):
the difference between this graph and the other one one is that y = the subkect
the vertex form is
y = a(x - b)^2 + c where (b,c) is the vertex
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zarkam21 (zarkam21):
OpenStudy (welshfella):
the vertex is (-5,-2)
zarkam21 (zarkam21):
Yes, I noted the difference and did the problem very slowly still can't seem to get the right answer
OpenStudy (welshfella):
I cant see that picture I#m afraid..
zarkam21 (zarkam21):
Ohh :(
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OpenStudy (welshfella):
first plug in the vetrex
y = a(x -(-5) + -2
y = a(x+ 5) - 2
now plug in x = -4 and y = -2 into the above and solve for a
zarkam21 (zarkam21):
Oh I see what I got wrong
zarkam21 (zarkam21):
I mixed up the x and y
zarkam21 (zarkam21):
Well I got 0
OpenStudy (welshfella):
-2 = a(1) - 2
a = 0
yea
let me check....
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OpenStudy (welshfella):
Oh the value of y = 2 when x is -4 ( not -2)
zarkam21 (zarkam21):
The answer would be -4?
OpenStudy (welshfella):
2 = (-4+5)a - 2
2 = a - 2
add 2 to both sides
zarkam21 (zarkam21):
So:
2=a-2
2+2=(a+2)(-2+2)
OpenStudy (welshfella):
2 = a - 2
2 +2 = a -2 + 2
2 + 2 = a
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zarkam21 (zarkam21):
4
zarkam21 (zarkam21):
Whewww thanks
OpenStudy (welshfella):
yw
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