Use this free body diagram to help you find the magnitude of the force F1 needed to keep this block in static equilibrium.
A.) 15.1 Newtons
B.) 36.3 Newtons
C.) 63.5 Newtons
D.) 95.5 Newtons

Question

Use this free body diagram to help you find the magnitude of the force F1 needed to keep this block in static equilibrium.
A.) 15.1 Newtons
B.) 36.3 Newtons
C.) 63.5 Newtons
D.) 95.5 Newtons

jamessarah210 · Answer

Here id the address: http://cdn.ple.platoweb.com/PCAP-ASSETS-PROD/a17dc1639e0641d9925d5fdbe6cd5ea8 Please help me?

ljetibo · Answer

So add the forces together. 

The left-right kind of motion will obviously be out of balance because currently you only have 1 force acting to the left of the body. Add a second force on the right of the body that is of the same magnitude.

The top-bottom motion will pull the object down because that force is much stronger than the top force and the resultant force is F1-F2. On the right hand side you have to add this difference to your force, but in opposite direction to cancel it. What do you get?
$$F = F_3 \hat x + (F_2-W)\hat y$$
now apply the formula to find the angle of a vector and x axis.

jamessarah210 · Answer

Thank you.