Question

help! Help with Geo!

Answer 1

May I help?

Answer 2

sure!

Answer 3

3mar it is public question

Answer 4

No need for you to ask me that anymore 3mar.

Answer 5

Are you familiar with trigonometric functions?

Answer 6

Ok
Just in case of someone else helps, I let him do it.

Answer 7

Not really :(

Answer 8

Can you look at this?

Answer 9

yeah, let me open it up.

Answer 10

csc=cosecant=cosec
So
\[\csc A=\frac{ ? }{ ? }\] ?

Answer 11

Thank you for the medal!
But I want you to share steps with me, please.

Answer 12

Yeah, I am just thinking so give me a min.

Answer 13

Take your time.

Answer 14

thanks

Answer 15

You can use that for help.

Answer 16

Sorry I am taking a while.
You can go help others while I do this :)

Answer 17

\[\frac{ 12 }{ 9 }\]Is that correct?

Answer 18

@3mar

Answer 19

\(\csc \theta = \dfrac{hypotenuse}{opposite} \)

Answer 20

yeah I got that mathStudent.

Answer 21

Notice correct side length in red figure.

Answer 22

I think it is not correct.
Let's say that\[cosec \theta =\frac{ 1 }{ \sin \theta }\]
ok?