Solve the compound inequality 6b < 24 or 4b + 12 > 4. @phi
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OpenStudy (brooke..help00):
There is multiple choice btw//
OpenStudy (phi):
6b < 24
any idea what to do? (I would divide both sides by 6, and simplify)
OpenStudy (brooke..help00):
so b > 4
OpenStudy (phi):
you are not allowed to change the < to a >
so close, but try again
OpenStudy (brooke..help00):
b < 4
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OpenStudy (phi):
yes. and notice the "big side" of < is next to the 4. that means 4 is bigger than b
or (same thing)
the "small side" of < is next to "b" , so b is smaller than 4
now we do the next part
4b + 12 > 4
OpenStudy (phi):
The first step is add -12 to both sides
can you do that ?
OpenStudy (brooke..help00):
Yes- 4b>-8
OpenStudy (brooke..help00):
not negative4
OpenStudy (phi):
ok, now divide both sides by 4
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OpenStudy (brooke..help00):
b>-2
OpenStudy (phi):
so if either b> -2 or b < 4
is true, then the inequality is true
notice that no matter what value we pick for b it will either be bigger than -2
or less than 4 (and sometimes both)
in other words, all values will work.