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can you walk me through 2(x+2)^2 +3
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PEMDAS do u know what that is
\[2(x+2)^2 +3\]
\[2x^2+8x+8+3\]
ya after you distribute the square where do you go
its not 8x its 16x
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\[(2x^2)+(8x)+(8+3)\]
its not (8x) because 2 x 2 = 4 then 4 x 4
\[2(x^2+2^2)+3\]
right?
no it would be ( 2x + 4) ^2 +3 then go from there
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then I have 2x^2+8+3 or 2x^2+11
no its not because e2x^2 is 2x times 2x so 4x^2 + 16 + 3
the power of two means double the same number not times 2
so it would be 4 times 4 = 16
4x+19
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yes then 4x= -19
find x
2(x+2)^2 +3 = 2(x^2 +4x +4) +3 = 2x^2 +8x +8 +3 = 2x^2 +8x +11 @Awolflover1 your result is right sure
so what you need to do - solve it for x ? in this case discriminant = 64-88=-24 <0 what mean that have not real roots hope helped
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