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Physics 26 Online
OpenStudy (pendragon):

can anyone can help me to calculate the battery current and equivalent resistance of this network...please ill give medal

OpenStudy (pendragon):

OpenStudy (pendragon):

@pooja195

OpenStudy (pendragon):

@mhchen @LifeIsADangerousGame

OpenStudy (daniellelovee):

follow this http://www.physicsclassroom.com/class/circuits/Lesson-4/Parallel-Circuits

OpenStudy (pendragon):

im confuse with the humps on it, is 8,6,12,4 are all parallel?

OpenStudy (pendragon):

@Frostbite

OpenStudy (pendragon):

@inkyvoyd

OpenStudy (pendragon):

@Will.H @mww

OpenStudy (pendragon):

@sissyedgar @JFraser

OpenStudy (sissyedgar):

I don't know. Sorry!

OpenStudy (radar):

Yes, they are all in parallel. The drawing is deliberately confusing, but if you spend some time following it, it will become clear.

OpenStudy (radar):

Now just calculate the equivalent resistance of the parallel network, and you are home free.

OpenStudy (pendragon):

8/5 ohms , thanks @radar

OpenStudy (pendragon):

sir @radar are you familiar with wye- delta problems?

OpenStudy (radar):

Having been retire since 1994, I have forgotten, but I am capable of researching Google lol.

OpenStudy (radar):

What did you get for the battery current in this problem?

OpenStudy (pendragon):

i use ohms law, 24v=(8/5) I...... I=15 A

OpenStudy (radar):

Very good.

OpenStudy (dallascowboys88):

Yep

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